# 0.999... = 1

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0.999... = 1: Prove that 0.999 (repeating to infinity) isn't equal to 1.

Proof 1:

x = 0.999...

10x = 9.999...

10x - x = 9.999... - 0.999...

9x = 9

x = 1

x = 0.999...

10x = 9.999...

10x - x = 9.999... - 0.999...

9x = 9

x = 1

Proof 2:

0.333... = 1/3

0.666... = 2/3

0.999... = 3/3 = 1

0.333... = 1/3

0.666... = 2/3

0.999... = 3/3 = 1

Proof 3:

All numbers that aren't equal to each other will have a number(s) that comes in between.

x < x+1 --- The number that could come in between of x and x+1 could be x+1/2.

So, give a number that comes in between 0.999... and 1.

All numbers that aren't equal to each other will have a number(s) that comes in between.

x < x+1 --- The number that could come in between of x and x+1 could be x+1/2.

So, give a number that comes in between 0.999... and 1.

You (as Con) will try to prove 0.999... (repeating to infinity) IS NOT EQUAL TO 1.

Round 1

0.999... = 1: Prove that 0.999 (repeating to infinity) isn't equal to 1.

Proof 1:

x = 0.999...

10x = 9.999...

10x - x = 9.999... - 0.999...

9x = 9

x = 1

Proof 2:

0.333... = 1/3

0.666... = 2/3

0.999... = 3/3 = 1

Proof 3:

All numbers that aren't equal to each other will have a number(s) that comes in between.

x < x+1 --- The number that could come in between of x and x+1 could be x+1/2.

So, give a number that comes in between 0.999... and 1.

You (as Con) will try to prove 0.999... (repeating to infinity) IS NOT EQUAL TO 1.

I am here to expose a lie. This is taught in official school math but is an absolute lie.

1/3 is not 0.3333.... with a '3' at the end. It is 0.333... that is eventually supposed to change into a value that is a 'third' but doesn't exist. So it will be 0.333...0333... over and over again.

The idea that because 0.999... is going on forever it's somehow less impossible or stupid than a number which doesn't have the identical digit throughout its infinite series, is nothing but pseudointellectual deception. 0.999... is meant to end in a 0 theoretically. 0.000... with a '1' at the end of 0's is not less possible to exist or less 'real' at all.

The difference between 0.999... and 1.000... either exists or 0.999... doesn't exist at all numerically and therefore it can't be equal to 1.

Round 2

The number in the middle is 0.999... with a '05' at the end. Similarly 0.999... itself has a '9' at the end that is meant to also theoretically be followed by infinite 0's (since all numbers have that following and the infinite 9's must end in a 9) so it's just as impossible of a value as the midpoint between it and 1.0000...

**Scenario 1 is HOCUS POCUS BBBBBBBBBOOOOOOOOOOOOOOOOOOOOOOGGGGUUUUUUUUUUUUUUUUUUSSSSSSSSSSS**

What you did with 'x' in the scenario is nothing more than a magic trick due to limitations of algebra and the fact that 0.999... is a fake value that doesn't even exist as you never reach the last 9. Try and reverse engineer it. Do it with x = 1 at the start and get me 0.999... at the end. You can't, meaning it's a pseudointellectual hoax.

**Let's see Scenario 3...**

All numbers that aren't equal to each other will have a number(s) that comes in between.x < x+1 --- The number that could come in between of x and x+1 could be x+1/2.So, give a number that comes in between 0.999... and 1.

oh. I handled that at the start of this Round.

Round 3

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Round 4

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1 and 2 have 1.1, 1.2, 1.2

1.1 and 1.2 have 1.11, 1.12, 1.13

1.12 and 1.13 have 1.111, 1.112, 1.113 and so on.

Whole integers can be represented as fractions or decimals.

You made this up. No math textbook has ever listed this as a fact of math that I'm aware of, and I'm pretty good at math.

it's simple. 0.99999... is an irrational number, and 1 is a rational number. 0.99999... is a decimal and 1 is a whole integer. By definition these cannot be the same number as they belong to mutually exclusive categories. I could draw a Venn diagram in Microsoft Paint if that would help you understand the concept.