Most Irrational Number Is?

Author: ebuc

Posts

Total: 6
ebuc
ebuc's avatar
Debates: 0
Posts: 4,198
3
2
4
ebuc's avatar
ebuc
3
2
4
Go to 10:50 to see the final conclusion, and it is opposite of what most people would think is the answer. Tho earlier stuff in vid is very explanatory for finding finite rationality numbers and the pathway to understanding his conclusion in more depth. Mathologer, got to love this guy. eh? Or not, depending. I'm not a math person, yet I find myself watching some of his stuff to see what I glean or winnow out from it, what might be useful to my limited math explorations.


K_Michael
K_Michael's avatar
Debates: 38
Posts: 749
4
5
10
K_Michael's avatar
K_Michael
4
5
10
-->
@ebuc
Actually the most educational thing I've seen on this site. Props for having the balls to discuss it here even if it doesn't get any traction.
ebuc
ebuc's avatar
Debates: 0
Posts: 4,198
3
2
4
ebuc's avatar
ebuc
3
2
4
-->
@K_Michael
Actually the most educational thing I've seen on this site. Props for having the balls to discuss it here even if it doesn't get any traction.
It was just the latest thing I accidentalently came across, as it played after this vid below.

It was the K4 SImple <> K5 more complex vertex thingy that I was less familiar with.

K8 may be maximum for torus, is what he appears to say in the video. I dunno.
Go to 7:50 in this utube link  https://www.youtube.com/watch?v=MhLBowZOdIo

And the above came as result of other explorations Ive been doing for few years with explorations for my cosmic space-time torus.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Why 7?
 
7 phase transition of 3-fold tet through 2-fold hexagon. ......4-5-6-- --6-5-4 wherein each polyhedral side/face/opening is counted in Fullers graphic


Also correcting, that, no number higher than 7 precedes the isolated set of 7's below

There are six, 6's that precede 7 in Pi^3. Three 3's, Three 2's. One 4 and one 5.
Also in Pi^3, 66 { twice } precedes 7 and  overall occurs five times.

55 ---see fibonancci 10th 11th position---  precedes 7 on 18th line of text, 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

...........3, 4, 6, 12.....6, 10, 15 = 7 axis sets { 4 + 3 }---{ 4-fold-4 + 5-fold-3 }

3rd powering aka XYZ or, as abc in Micho Kaku’s “ Hyper-space “ cube { abc-d }

7 occurs in overall 7th position in both sets of powering, below.

Pi^3 = 31. { 31 left-right-skew primary great circles of 5-fold icosahedron = 62 }
 
……..…………….………...0062 7
…..…………….....66802998201 7
…..….………………....…..….54 7
…...………………….......631506 7
......10139520222528856588510 7
…….....69414453810380639491 7
……..…………………….......465 7
…..…………...…………......0603 7
…..……………………….......566 7
.....010326028861930301219615 7
…….…..…………....…23366223 7
……..…………….....……520161 7
……..……….………......6523396 7
……..…………….……......…....2 7
...3356139415442538825403366 7
…………………………......……...7
……………………………......…2 7
……………………………........55 7 <<<<<<<<<<<<<<
………………………......6626396 7
……......50285320332468630426 7
..9 ?????????????????????????
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

In Pi^4/4 the highest number preceding the isolated 7, is again, a 7. Five 2's. Four 1's. One 4. One 6. One 3. One 0.

Next set is my re-normalization of P^4 { XYZ/abc-d } via, dividing by four.
…..Pi^4 / 4 = 24. { 24 chords of VE, 24 radii of VE = equanimity }
 
…………………………………........…………..3522 7
…………………………….........……………………2 7
………………………….....585.00.60930911.00.831 7
………………………….........……………………..21 7
…………………………………………….........…..62 7
……………………………………..........……………...7
……………………………….........…8124318964181 7
……………………………….........135542286696484 7
……………………………………..............………492 7
……………………………………..........…..13864206 7
……………………………….........……..………..9904 7
……………………………..........53046680868824813 7
……………………………………............……………...7
………………………………............42293312930961 7
…………………………………...........0432814161042 7
………………………………..............8260203588450 7
……………………………….............90811149321594 7
5128320493833159839246533588943656095299 ????


I think there may be another another set of seven face axi in Synergetics,--or another of his books---  of the edge truncated tetrahedron.

And there is the minimal  set of 7 color to map faces that are not adjcent to each other on a torus.

..." For instance, on a torus (a doughnut-shaped surface), we have the Seven-Color Theorem, along with many eye-catching ways of proving that seven colors are necessary. Here is a collection of maps on surfaces that are topological tori, each map having seven countries* all of which touch all of the others."...



RationalMadman
RationalMadman's avatar
Debates: 556
Posts: 19,354
10
11
11
RationalMadman's avatar
RationalMadman
10
11
11
-->
@K_Michael
Bonus lesson. ;)

15 days later

ebuc
ebuc's avatar
Debates: 0
Posts: 4,198
3
2
4
ebuc's avatar
ebuc
3
2
4
This following is in reference to Bucky Fullers Synergetics relationship of volume between the Vector Equilibrium aka the 4-fold cubo-octahedron of 20 tetrahedra, to the VE’s first contracted phase as the below that is relates specifically the icoashedron whose volume is 18.51 tetrahedra, in Synergetics.

The 18.51 is extended out to 1000 irrational places and Ive found those interesting numbers to me and other oddities. 

7 Is most unique number { see heptagon only irrational angles out of first 10 polygons }

00 is in italics stems from my Pi^3 = 31.00 62 7...explorations

55 is in bold { not a Pi^3 reference but a fibonacci reference 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377 }

66 Pi^3{ see above } and Pi^4 minus Pi^3 equals 66.4 my Cosmic Pi Time
24 ergo equanimity

...1} On 43rd irrational line, we have 24 integers/digits/numbers, and 00, 55 66 and 7 all occur in this line of 24 digits/integers/numbers. 24 via the Vector Equilibrium/Cubo{6}-octa{8}hedron represents equanimity.

{43rd..24{ equanimity } integers on this line35} ….005606604251551546984 7

...2} on t 44th line  of irrationals, there is a eight sets of duplicity 22, 33, 55, 44, 11, 33, 66, 11  and one triplet 888

3922141332019095514888544119650680633926366911320296903490 7

….3} on 9th irrational line there is set of five 9's

……………………………….....…......21021999990349396147413 7

This latter five 9’s make my antenna go Bing!/Wow!

18.
………………………..5122958682191611960098992926545319235 7
…………………………………..14269136401526159688601669119 7
…………………………………………………………...6850638983447
…………………………………………………………………….38526 7
…………………………………………………………………………....7

………………………………………………………..84055625334809 7
………………………………………………………………………..205 7
……………………………….11394236555830841049501522913155 7
……………………………………………21021999990349396147413 7
……………………………………………………………………404441 7

…………………………………………………………………………..9 7
………………………………………………………………………3163 7
……………………………………..5012443929214164596239114023 7
…………………………………………………………………………29 7
………………………………………………………………………….....7

……………………………………………………………095600016208 7
…………………………………………………………....388255161535 7
………………………………………………………..343281938441425 7
……………………………………………………………………….......1 7
……………………………………………………480996481367399086 7

……………………………………………………………………………...7
………………………………………………………………………...........7
……………………………………………………………………9028093 7
……………………………………………………………………………...7
……………………………………………………………………....18281 7

………………………………………………………………………….895 7
………………………………………………………………..1650940240 7
……………………………………………………………….…………964 7
…………………………………..1968291888628513646128089916285 7
…………………………………………………………………….......4659 7

………………………………………...623896164132974651533726566 7
……………………………………………………………………………..8 7
…………………………………………………..00849448946011252431 7
……………………………………………………………...898909827884 7
……………………………………………3104165849919489053890990 7

……………………………………………………..492616962954098499 7
……………………………………………………………...344153584180 7
……………………………………………………………………….............7
……………………………b…………………………………………..0613 7
………………………………………………..5320505990195898934448 7

……………………………………………………...462930095640804629 7
………………………………………….………........………………………7
{43rd..24 integers on this line}……............35005606604251551546984 7
3922141332019095514888544119650680633926366911320296903490 7
………………………………………………………………………...86243 7

…………………………………………………………….……………..……7
……………………………………………………………….…0423858608 7
……………………………………………………………………………903 7
……………………………………………………..5420609706664546066 7
……………………………………………………………..65610162430051 7

92089695813 7 425832682498286291909189322612160943202242420717529241144521359436
643114811248952056054193598295250551591114305578934437412
740722724466451761239825539760290514684254836216235810698
669739843203784701711241399111594510295289561427686571337
154906163221983172119998846360928818489816228625976865425
516130630133434160307574478272859


Previously I posted my P^4 minus P^3 and forgot to list the rational 24 in first line, so here that is again.

24.
…………………………………........…………..3522 7
…………………………….........……………………2 7
………………………….....585.00.60930911.00.831 7
………………………….........……………………..21 7
…………………………………………….........…..62 7
……………………………………..........……………...7
……………………………….........…8124318964181 7
……………………………….........135542286696484 7
……………………………………..............………492 7
……………………………………..........…..13864206 7
……………………………….........……..………..9904 7
……………………………..........53046680868824813 7
……………………………………............……………...7
………………………………............42293312930961 7
…………………………………...........0432814161042 7
………………………………..............8260203588450 7
……………………………….............90811149321594 7
5128320493833159839246533588943656095299 ????
Shila
Shila's avatar
Debates: 0
Posts: 2,736
3
3
5
Shila's avatar
Shila
3
3
5
-->
@K_Michael
-> @ebuc
Actually the most educational thing I've seen on this site. Props for having the balls to discuss it here even if it doesn't get any traction. 
But he didn’t colour the balls. So the four colour theorem cannot be applied.